Subnetting - How To Calculate Network Address

Jan 11, 2012

Given the IP address of and the network mask of answer the following:

What is the network address?

What is the broadcast address?

What is the valid host IP range?

What I have done so far:

Part 1 - Broadcast address - 10101100.00010000.00001010.00010110 - 11111111.11111111.11111111.11110000

Researching different ways to find the Broadcast address I took the binary IP address and replaced all numbers with 1's for the host bits identified in the subnet mask and came up with: - 10101100.00010000.00001010.00011111

Is that the correct Broadcast address?

Part 2 - Network address

I am not sure what is meant by the network address and all my research has come up with either MAC addresses (obviously wrong) or CIDR notation...How do I calculate the network address?

Part 3 - List of valid IP's

Using the same address I did the following:

28 is closest to 32 (block wise) so 32 - 28 = 4... 2 ^ 4 = 16 (block size)

IP address listing:
and so on...

The IP address in question is and falls in the - block...

Is this the correct list of valid IPs?

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Subnetting A Class C Ip Address?

Dec 13, 2011

I am looking a old exercise I did last year about subnetting and I am wondering if is possible to subnet: /22

I wrote down, last year, that:

16 bit are assigned to network
6 to subnet
10 to hosts

when actually I see a class C ip address with 10 bit assigned to hosts. So, how many bit do I have for network, subnet and hosts?

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How can know the Broadcast address before subnetting? I know how to calculate the broadcast address , but don't understand 'Broadcast address before subnetting'?

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I wanna subnet my Network to increased performanced but im alil confused hereWhen looking at my ROUTER STATUS this is what i have.

gateway ip XX.XX.X.X
ip address

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I am currently trying to understand Subnetting via CCNA. My progress is going well,I understand the class below:

Class A 0-127 Max IP 2^24 = 16777216
Class B 128-191 Max IP 2^16 = 65536
Class C 192-223 Max IP 2^8 = 256

However I have seen an example from an ip calculator website, and noticed this :

Address: 11000000.10101000 .00000001.00000000
Netmask: = 16 11111111.11111111 .00000000.00000000
Wildcard: 00000000.00000000 .11111111.11111111
Network: 11000000.10101000 .00000000.00000000 (Class C) - I would have thought this would have been Class B?
Broadcast: 11000000.10101000 .11111111.11111111
HostMin: 11000000.10101000 .00000000.00000001
HostMax: 11000000.10101000 .11111111.11111110
Hosts/Net: 65534 (Private Internet)

Is this an invalid IP/masks as the max hosts is 65534 (which should be class B?). If so shouldnt the IP address range from 128-191- eg 172.16 (I know that CIDR is the amount of 1's. ).What calculates the class is it the netmask or the range of the first octet?

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Apr 5, 2012

we currently use the ASA 5505 router. We would like to create another subnet inside our LAN because we are running out of IP addresses.
current subnet info:
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Another theory is that the NAT ip for clients is different than the actual interface IP, so that is behaving differently. For example, once the xlate times out, the IP used for the xlate is no longer active and any return packets to the interface would also error out - be refused. If the xlate was using the interface IP, that it would always respond in some way?
I can bump 106001 down to notification (5) or informational (6) level.

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- IP packet of 1500 bytes comprises 1480 bytes of data and a 20-byte header.
- In the first intermediate network, the packet size of 1024 bytes allows for 1000 bytes of data plus a 20-byte IP

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I can install the printer to the Toshiba and it 'knows' the IP address to connect using a standard TCP/IP port that is installed in Printer ports. The printer installs fine and I ca nsend print jobs to the printer but they do not print. Eventually an error message comes up saying the job was not sent to the printer.

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