Subnetting - How To Calculate Network Address

Jan 11, 2012

Given the IP address of 172.16.10.22 and the network mask of 255.255.255.240... answer the following:

What is the network address?

What is the broadcast address?

What is the valid host IP range?

What I have done so far:

Part 1 - Broadcast address
172.16.10.22 - 10101100.00010000.00001010.00010110
255.255.255.240 - 11111111.11111111.11111111.11110000

Researching different ways to find the Broadcast address I took the binary IP address and replaced all numbers with 1's for the host bits identified in the subnet mask and came up with:

172.16.10.31 - 10101100.00010000.00001010.00011111

Is that the correct Broadcast address?

Part 2 - Network address

I am not sure what is meant by the network address and all my research has come up with either MAC addresses (obviously wrong) or CIDR notation...How do I calculate the network address?

Part 3 - List of valid IP's

Using the same address 172.16.10.22/28 I did the following:

28 is closest to 32 (block wise) so 32 - 28 = 4... 2 ^ 4 = 16 (block size)

IP address listing:
172.16.0.0
172.16.16.0
172.16.32.0
172.16.48.0
172.16.64.0
and so on...

The IP address in question is 172.16.10.22 and falls in the 172.16.0.0 - 172.16.15.0 block...

Is this the correct list of valid IPs?

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Netmask: 255.255.0.0 = 16 11111111.11111111 .00000000.00000000
Wildcard: 0.0.255.255 00000000.00000000 .11111111.11111111
=>
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